the sum of 3 consecutive multiple of 3 is 54
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7
15+18+21
fifteen eighteen and tweentyone may be
Answered by
19
ANSWER :
Let the consecutive multiples be 3x, ( 3x+3 ) & ( 3x+6 )
According to question, the sum of these multiples is 54
=> 3x + ( 3x+3 ) + ( 3x+6 ) = 54
=> 3x + 3x + 3 + 3x + 6 = 54
=> 9x + 9 = 54
=> 9( x + 1 ) = 54
=> x + 1 = 6
=> x = 5
Therefore, the multiples are :
3x = 3*5 = 15
3x + 3 = 15 + 3 = 18
3x + 6 = 15 + 6 = 21
The multiples are 15,18 and 21.
Hope this helps you☺☺
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