Question

The sum of 3 consecutive multiples of 11 is 198. find the multiples.

Answer 1

Heya!
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↪Let the consecutive multiples be x , ( x + 11 ) and ( x + 22 ) respectively!


▪Now , According to the given question ->
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=> x + x + 11 + x + 22 = 198


=> 3x + 33 = 198


=> 3x = 198 - 33

=> 3x = 1 65

=> x = 165/3


=> x = 55


↪Hence the Multiples are 55 , 66 and 77 respectively!


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Answer 2

let 3 consecutive multiples are x,x+11,x+22
x+x+11+x+22=198
3x+33=198
3x=198-33
3x=165
x=55
So,multiples are-:
x=55
x+11=66
x+22=77
Hope it helps! !