The sum of 3 consecutive multiples of 11 is 363. Find the smallest among them. *
1 point
a) 77
b) 99
c) 110
d) 121
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Answer:
==: 11x + 11x + 11 + 11x + 22 = 363
==: 33x + 33 = 363
==: x + 1 = 11
==: x = 10
Hence, numbers are 110 , 121 and 132
110 is the smallest
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