Question

The sum of 3 consecutive multiples of 11 is 99 find the numbers

Answer 1

let the number be x

three consecutive multiples of 11 = x, x+11, x+22

according to question

x + (x+11) + (x+22) = 99

x + x + 11 + x + 22 = 99

3x + 33 = 99

3x = 99 - 33

3x = 66

x = $\frac{66}{3}$

x = 22

x+11 = 22 + 11 = 33

x + 22 = 22 + 22 = 44

therefore the numbers sre 22, 33, 44

Answer 2

Answer:

Step-by-step explanation:

1 число-11n,

2 число-11(n+1),

31 число-11(n+2). Сумма этих чисел  99.  

11n+11(n+1)+11(n+2)=99,

33n+33=99,

33n=66

n=2

1 число-11*2=22,

2 число-11(2+1)=33,

31 число-11(2+2)=44.