Question

The sum of 3 consecutive multiples of 12 is 216,find the multiples

Answer 1

Answer: X+12+X+24+X+36=216

3x+72=216

3x=216-72

3x=144

X=144/3

X=48

The three consecutive multiples of 12 which sum up to 216 are:

48+12=60

48+24=72. And,

48+36=84

Step-by-step explanation: