The sum of 3 consecutive multiples of 12 is 216,find the multiples
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Answer: X+12+X+24+X+36=216
3x+72=216
3x=216-72
3x=144
X=144/3
X=48
The three consecutive multiples of 12 which sum up to 216 are:
48+12=60
48+24=72. And,
48+36=84
Step-by-step explanation:
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