Question

the sum of 3 consecutive multiples of 3 is 72.what is the second largest number

Answer 1

Let the three consecutive multiples of 3 are 3x , 3x+3 , 3x+6 .

3x + 3x + 3 + 3x + 6 = 72

9x + 9 = 72

9x = 63

x = 63/9 = 7 .

3x = 21
3x+3 = 24
3x+6 = 27

Therefore, the three consecutive multiples of 3 are 21 , 24 , 27 .The second largest number is 24 .

Answer 2

Let the three consecutive multiples of 3 as 3x , 3x+3 , 3x+6 respectively.
ATQ,
3x + 3x + 3 + 3x + 6 = 72 
9x + 9 = 72 
9x = 63 
x = 63/9 
x = 7 .
Now,
1st. no = 3x = 21 
2nd no. = 3x+3 = 24 
3rd.  no . = 3x+6 = 27 

hence the second largest no. is 24.