Question

the sum of 3 consecutive multiples of 4 is 444 . find rational no.

Answer 1

let the first no. be x
then next comsecutive multiples of 4 are
x+4,x+8
A.T.Q,
x+x+4+x+8=444
3x+12=444
3x=444-12
3x=432
x=144
the first no.is 144
the next consecutive no.s are 148 and 152

Answer 2

Hi!
#Ur Ans
__________

There are three consecutive number
X, (X+1), (X+2)

& Every number have multiple 4

Then

4x +4(X+1) +4(X+2) = 444

4x +4x +4 +4x +8 = 444

12x +12 = 444

12x = 444-12

12x = 432

X = 432/12

X = 36

Hence number are
X = 36
X+1 = 37
X+2 = 38.


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