Question

the sum of 3 consecutive multiples of 5 is 195. find these numbers

Answer 1

Let the first multiple be x
Second multiple be x+5
And third multiple be x+10
A/q
$x + x + 5 + x + 10 = 195 \\ 3x + 15 = 195 \\ 3x = 195 - 15 \\ 3x = 180 \\ x = \frac{180}{3}$
$x = 60$
So,
First multiple=60
Second multiple =60+5=65
Third multiple=60+10=70