The sum of 3 consecutive multiples of 5 is 945 find the largest number
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Answer:
Let the first multiple be 5a
Second multiple = 5a + 5
Third multiple = 5a + 1
According to question
5a + 5a + 5 + 5a+ 10 = 945
=> 15a + 15 = 945
=> 15a = 930
=> a = 62
First multiple = 62 × 5 = 310
Second multiple = 310 + 5 = 315
Third multiple = 310 + 10 = 320
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