Question

the sum of 3 consecutive multiples of 6 is 126. find these 4 multiples ​

Answer 1

Answer:

let first multiple of 6 be x

second one is x+6

third one is 12+x

x+x+6+x+12=126

3x+18=126

3x=108

x=36

hence, three multiples are 36,42 and 48