the sum of 3 consecutive multiples of 6 is 666 find these multiple
Answers
Answered by
10
let first multiple =6x
acc to question
6x+6(x+1)+6(x+2)+6(x+3)=666
6x+6x+6+6x+12+6x+18=666
12x+12x+36=666
24x+36=666
24x=666-36
24x=630
x=630/24
x=26.25
acc to question
6x+6(x+1)+6(x+2)+6(x+3)=666
6x+6x+6+6x+12+6x+18=666
12x+12x+36=666
24x+36=666
24x=666-36
24x=630
x=630/24
x=26.25
07rajput23:
answer is wrong
OK I had not read multiple of 6 that's way it happened
ok
Answered by
3
let these multiple be x-1,x,x+1
from 1st condition
x+1+x+x-1=3x=666
x=666/3=111
hence this multiple are
110,111,112
from 1st condition
x+1+x+x-1=3x=666
x=666/3=111
hence this multiple are
110,111,112
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