Question

The sum of 3 consecutive multiples of 7 is 651. Find the multiples.​

Answer 1

Refer the above attachment.

Hope this helps...!

Answer 2

Let the 3 Consecutive multiples of 7 be (x + 7), (x + 14) and (x + 21)

Sum of 3 consecutive multiples of 7 = 651

(x + 7) + (x + 14) + (x + 21) = 651

x + 7 + x + 14 + x + 21 = 651

3x + 42 = 651

3x = 651 - 42

3x = 609

x = 609/3

x = 203

First multiple of 7 = (x + 7) = 203 + 7 = 210

Second multiple of 7 = (x + 14) = 203 + 14 = 217

Third multiple of 7 = (x + 21) = 203 + 21 = 224

Verification:

210 + 217 + 224 = 651

651 = 651

LHS = RHS

So, 210, 217 and 224 are required multiples of 7.