Question

 The sum of 3 consecutive multiples of 9 is 81. Find the smallest one​

Answer 1

Answer:

Let smallest multiple be x.

Then other two multiples are x + 9 and x + 18.

ATQ

x + x + 9 + x + 18 = 81

=> 3x + 27 = 81

=> 3x = 54

=> x = 18

so smallest multiple = 18

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Answer 2

Answer:

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