Question

the sum of 3 consecutive multiples of 9 is 999 find these multiples

Answer 1

Let,
Consecutive multiples are

• 9x
• 9x +9
• 9x +18
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According to the question,

9x +9x +9+9x +18 = 999

9x +9x +9x +9+18 = 999

27x + 27 = 999

27x =999-27

27x =972

x = 972/27

x=36


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Then,

Multiples are

• 9x = 9×36 = 324

• 9x +9= 324+9=333

• 9x +18 = 324+18= 342




I hope this will help you


-by ABHAY

Answer 2

Hii...☺

Here is your solution...

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⭐ Let Three consecutive multiples of 9 be:

=> 9x, 9x + 9 , 9x + 18

Their sum = 999

=> 9x + 9x + 9 + 9x + 18 = 999
=> 27x + 27 = 999
=> 27( x + 1 ) = 999
=> x + 1 = 999/27
=> x + 1 = 37
=> x = 37 - 1
=> x = 36

Hence, 9x = 9 × 36 = 324
=> 9x + 9 = 324 + 9 = 333
=> 9x + 18 = 324 + 18 = 342

Hence, the required three multiples of 9 that are added to obtain 999 are 324, 333 and 342.

Thanks.....☺