Question

the sum of 3 consecutive multiplies of 11 is 363. find these numbers

Answer 1

Let the first multiple be x
Second multiple be x+11
And third multiple be x+22
A/q
$x + x + 11 + x + 22 = 363 \\ 3x + 33 = 363 \\ x = 110$
So,
First multiple =110
Second multiple
$= x + 11 \\ = 110 + 11 \\ = 121$
Third multiple
$= x + 22 \\ = 110 + 22 \\ = 132$

Answer 2

hope you will understand this