Question

The sum of 3 consecutive natural number is 36.what are the number?​

Answer 1

let the numbers be x , x+1 and x+2

as per the question

$= > x + x + 1 + x + 2 = 36 \\ = > 3x + 3 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 36 \\ = > x + 1 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 12 \\ = > x \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 11$

the 3 numbers are 11 , 12 , and 13

Answer 2

Answer:

The consecutive natural numbers are 11, 12, 13

Step-by-step explanation:

Let,

The consecutive natural numbers are :

• x
• x + 1
• x + 2

★ According to the question :

⇒ x + (x + 1) + (x + 2) = 36

⇒ 3x + 3 = 36

⇒ 3x = 36 - 3

⇒ 3x = 33

⇒ x = 33 / 3

⇒ x = 11

★ x + 1 :

⇒ 11 + 1

⇒ 12

★ x + 2 :

⇒ 11 + 2

⇒ 13

Therefore,

The consecutive natural numbers are 11, 12, 13

★ Verification:

⇒ 11 + 12 + 13

⇒ 36

★ Total sum of 3 consecutive number is

Total sum of 3 consecutive number is 36