Question

The sum of 3 consecutive natural number is 36. Which are the numbers

Answer 1

Given :

The sum of 3 consecutive natural number is 36.

To find :

Find the numbers

Solution :

Let the number be first number be x , second number be (x+1) and third number be (x+2)

According to the given condition

Sum of 3 consecutive number = 36

=> x + (x+1) + (x+2) = 36

=> x + x + 1 + x + 2 = 36

=> 3x + 3 = 36

Take 3 as a common

=> 3(x+1) = 36

=> x + 1 = 36/3

=> x +1 = 12

=> x = 12 -1 = 11

Hence

First number = x = 11

Second number = (x+1) = 11 +1 = 12

Third number = (x+2) = 11 + 2 = 13

Verification :

Sum of consecutive numbers

= 11 + 12 + 13

= 36

Hence , Solution verified

Answer 2

Answer

Let the no. is x,x+1,x+2

x+x+1+x+2=36

3x+3=36

3x=36-3

3x=33

x=33/3

x=11

x=11

x+1=11+1=12

x+2=11+2=13