Question

The sum of 3 consecutive numbers 114 then the largest number is ...​

Answer 1

Step-by-step explanation:

let the first no. be X.

now the second will be X+1

and third will beX+2

A.T.Q

X+X+1+X+2=114

3+3X=114

3X =114-3

X=111/3

X=37

so the no. are 37,38,39

Answer 2

Given:-

• The sum of three consecutive numbers 114.

To Find:-

• Find the largest number.

Concept:-

• Let's go through the concept first. Form an equation firstly and substitute the given values in it by taking three unknown consecutive numbers and solve it.

Solution:-

Let the three consecutive numbers be x,x + 1 and x + 2

Sum of the numbers = 114

According to the question we have!

⟹ x + x + 1 + x + 2 = 114

⟹ (x + x + x) + (1 + 3) = 114

⟹ 3x + 3 = 114

⟹ 3x = 114 - 3

⟹ 3x = 111

⟹ x = 111/3

⟹ x = 37

Hence,

The First number is 37.

Now,Substitute the value of x in the consecutive numbers we had taken.

For x + 1,

⟹ x + 1

⟹ 37 + 1

⟹ 38

Hence,

The Second number is 38.

For x + 2,

⟹ x + 2

⟹ 37 + 2

⟹ 39

Hence,

The Third number is 39.

Therefore,

The three consecutive numbers are 37,38 and 39 and the largest number is 39.

Verification:-

x + x + 1 + x + 2 = 114

x = 37

⟹ 37 + (37 + 1 ) + (37 + 2) = 114

⟹ 37 + 38 + 39 = 114

⟹ 75 + 39 = 114

⟹ 114 = 114

⟹ LHS = RHS

Hence,

It is verified.

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