Question

the sum of 3 consecutive numbers is 192 find the numbers

Answer 1

ANSWER
...........

THE 3 CONSECUTIVE NUMBERS ARE

192 / 3
< 64 + 1 - 1 - 1>
= 63

Answer 2

Hi ,

Let ( x - 1 ) , x , ( x + 1 ) are the three

consecutive numbers ,

Sum = 192

x - 1 + x + x + 1 = 192

3x = 192

x = 192/3

x = 64

Therefore ,

Required 3 consecutive numbers are,

x - 1 = 64 - 1 = 63 ;

x = 64 ;

x + 1 = 64 + 1 = 65 :

I hope this helps you.

:)