The sum of 3 consecutive numbers is equal to 57
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Answer:
Let the 3 consecutive odd nos be x, x+2, x+4
x+x+2+x+4=57
3x=51
x=17
So the numbers are 17,19 and 21.
Step-by-step explanation:
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Answered by
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Answer-
Let x=integer # 1; then, x + 1= 2nd integer; and x + 2= 3rd integer.
x + (x + 1) + (x + 2) = 57
3x + 3 = 57
3x = 54
x1 = 18.
x2 = x + 1 = 18 + 1 = 19
x3 = x + 2 = 18 + 2 = 20
Check: 18 + 19 + 20 = 57 and, they are consecutive.
Here's what we know:
a + b + c = 57
a = b - 1
c = b + 1
Now that we have values for our variables, let's put them in:
(b - 1) + b + (b + 1) = 57
Simplify:
3b = 57
Divide both sides by 3:
b = 19
a = 19 - 1
a = 18
c = 19 + 1
c = 20
Check:
18 + 19 + 20 = 57
57 = 57
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