the sum of 3 consecutive numbers of 8 is 888. find these multiples
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HI Friend.
Let the 1st consecutive number = x
2nd consecutive number = x+8
3rd consecutive number = x+8+8 ⇒x+16
A\Q sum of the numbers=888
x+(x+8)+(x+16)=888
x+x+8+x+16=888
3x+24=888
3x=888-24
3x=864
x=864\3
x=288
∴1st number=288
2nd number=(x+8)⇒288+8=296
3rd number=(x+16)⇒288+16=304
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