Math, asked by akansha8223, 11 months ago

The sum of 3 consecutive odd integers is 57, what is the smallest integer?

Answers

Answered by piyush5843
0

let the integers be x, (x+2),( x+4)

sum of these is 57

x + (x +2) + (x +4 )=57

3x+6= 57

3x= 57-6

3x= 51

x = 51/3

x=17

1st integer=17

2nd integer=19

3rd integer = 21

thus....the smallest integer is the first one i.e. 17

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