Question

The sum of 3 consecutive odd integers is 63. find the three integers?

Answer 1

Answer:

Let the nos be x, x+2, x+4

ATQ

X + (x+2) + (x+4) = 63

3x + 6 = 63

3x = 57

X = 19

Therefore the nos are x = 19

X+2 = 21

X+4 = 23

Step-by-step explanation:

Answer 2

Answer:

three consecutive integer are = 10.5,21,31.5

Step-by-step explanation:

let the first consecutive integer be x then second consecutive integer be 2x and the third consecutive integer be 3x

x+2x+3x= 63

6x= 63/6

x= 10.5

x= 10.5 then

2x= 10.5×2 = 21

3x= 10.5×3= 31.5

10.5+31.5+21=63

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