the sum of 3 Consecutive odd number is 165 ,what is the sum of the largest number and twice the smallest number.
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the form of an odd number is 2n+1
largest number is 57
smallest number is 53
largest number is 57
smallest number is 53
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Thank you for asking this question, here is your answer:
The three consecutive odd integers: n, n + 2, and n + 4
n + (n + 2) + (n + 4) = 165
3n + 6 = 165
3n + 6 - 6 = 165 - 6
3n = 159
3n / 3 = 159 / 3
n = 53
1. n, or 53.
2. n + 2, or 55.
3. n + 4, or 57.
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