the sum of 3 consecutive odd numbers is 69. the smallest of the three is? pls explain with steps.
Answers
Answered by
3
x+(x+2)+(x+4)=69
3x+6=69
3(x+2)=69
x+2=23
x=21
consider the smallest number to be x
3x+6=69
3(x+2)=69
x+2=23
x=21
consider the smallest number to be x
saicharan06467:
sorry
1st number = x
2nd number = x+2
3rd number = x+4
x+(x+2)+(x+4)=69
3x+6=69
3x=69-6
3x=63
x=63/3
x=21
1st number = x = 21
2nd number = x+2=21+2=23
3rd number = x+4=21+4=25
In all these 21 is the smallest number.
2nd number = x+2
3rd number = x+4
x+(x+2)+(x+4)=69
3x+6=69
3x=69-6
3x=63
x=63/3
x=21
1st number = x = 21
2nd number = x+2=21+2=23
3rd number = x+4=21+4=25
In all these 21 is the smallest number.
isn't it odd numbers, so how it is x+1 and x+2?
my answer is write one.i just did it above
yes, ruth24 is right.odd numbers should be not taken as x+1 and x+2
the answer is 21.
yep. thank u
Answered by
2
1st number = x2nd number = x+23rd number = x+4
x+(x+2)+(x+4)=693x+6=693x=69-63x=63x=63/3x=21
1st number = x = 212nd number = x+2=21+2=233rd number = x+4=21+4=25
In all these 21 is the smallest number.
x+(x+2)+(x+4)=693x+6=693x=69-63x=63x=63/3x=21
1st number = x = 212nd number = x+2=21+2=233rd number = x+4=21+4=25
In all these 21 is the smallest number.
Similar questions