Question

The sum of (3) consecutive odd numbers is 990. find the numbers?​

Answer 1

Answer-

Let the first odd number = x

Second odd number = x+2

And the third odd number = x+4

According to the condition,

$= > x + x + 2 + x + 4 = 990 \\ = > 3x + 6 = 990 \\ = > 3x = 990 - 6 \\ = > 3x = 984 \\ = > x = \frac{984}{3} \\ = >x = 328$

∴ First odd number = x = 328

Second odd number = x + 2 = 328 + 2 = 330

third odd number = x + 4 = 328 + 4 = 332

Hence, the three consecutive odd numbers are 328, 330 and 332.

Note - You can also check it by adding all three numbers.

Example- 328+330+332= 990

Hope it helps:)

Answer 2

Answer:

Step-by-step explanation:

Given the sum of 3 consecutive odd number is 990

Let the First number be 'x' and second be 'x+2'

Third number be 'x+4'

Sum = 990

x + x + 2 + x + 4  = 990

3x + 6 = 990

3x = 984

x = 328

First number = x = 328

Second number = x+2 = 330

Third number = x+4 = 332