Question

The sum of 3 consecutives integers is 5 more than the smallest of a integer . Find the integer

Answer 1

Define x:

Let the smallest number be x

The other number is (x + 1) and (x + 2)

Solve x:

The sum is 5 more than the smallest integer

x + (x + 1) + (x + 2) = x + 5

x + x + 1 + x + 2 = x + 5

3x + 3 = x + 5

2x = 2

x = 1

Find the numbers:

Smallest = x = 1

The next number is x + 1 = 1 + 1 = 2

The next number is x + 2 = 1 + 2 = 3

Answer: The numbers are 1, 2 and 3

Answer 2

Hope it helps!

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