The sum of 3 consucative multiples of 11 in 363 find the multiples
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Answer:
Three consecutive multiples are 110,121 and 132 which has the sum of 363. 33C = 363; C = 33, By substituting C = 33 in numbers 11C, 11(C – 1) and 11(C + 1) we get values 110, 121, 132.
Step-by-step explanation :
In this we have to assume number consecutively and then add it
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Answered by
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Answer: 110 , 121 and 132
Step-by-step explanation:
Let the number's be x , x+11 , x+22.
x + x + 11 + x + 22 = 363
3x + 33 = 363
3x = 363 - 33 = 330
x = 330/3 = 110
x + 11 = 110 + 11 = 121
x + 22 = 110 + 22 = 132
Hence, the number's are 110 ,121 and 132.
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