The sum of 3 NO.in AP is 21 and their product is 231.Find Find the number.
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Let the three numbers of AP be a-d , a , a+d
Now
a-d + a +a+d = 21
=> 3a = 21
=> a = 7
Now
a-d × a × a+d = 231
=> 7-d × 7 ×7+d = 231
=> 49-d² = 33
=> d² = 16
=> d = 4
Hence, the numbers are 3 , 7 , 11
Thanks:)
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