Question

the sum of 3 no.in ap is 3 and their product is -35 find the no.​

Answer 1

Answer:

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Answer 2

Let the three numbers in AP be

(a-d) , a , (a+d)

Sum = 3

a-d+a+a+d = 3

3a = 3

a = 1

Product = -35

(a-d)(a)(a+d) = -35

Substitute a = 1

(1-d)(1)(1+d) = -35

1² - d² = -35

d² = 36

d = ±6

So the numbers are -5 , 1 , 7