The sum of 3 numb, a, b and c is 2468. a is 580 an b is twice of a. the value of c is
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Answer:
c = 728
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Given, a+b+c=2469
a=580
b=2a
So, b=2a=2×580=1160
Then, a+b+c=2468
or,580+1160+c=2468
or,1740+c=2468
or,c=2468-1740
or,c=728
The value of c is 728.
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