the sum of 3 number in an A. P is 27 the product of first and last number is 65 find the numbers
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Let the numbers are in AP be a - d, a, a + d
The sum of three number in A.P. is 27.
a - d + a + a + d = 27
3a = 27
a = 9
The product of first and last is 56.
(a - d)(a + d) = 56
a2 - d2 = 56
92 - d2 = 56
d2 = 81 - 56 = 25
d = ± 5
Then the numbers are 4, 9, 14 or 14, 9, 4.
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the answer is 9
plz make my answer brilliant if my answer is correct
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