The sum of 3 number whose ratio are 10 by 3 :21 by 5: 49 by8 is 4917.Find the number
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0/3x+21/5x+49/8x=4917.........(1)
x[10/3+21/5+49/8]=4917
x[10*5*8+21*3*8+49*3*5]
= 4917*3*5*8
x[400+504+734]=4917*3*5*8
x[1639]=590040
x=590040/1639=360
x=360.
put the value of x into equation 1 and we get,
10/3x=1200,
21/5x=1512,
49/8x=2205.
we get the three numbers are 1200, 1512, and 2205.
x[10/3+21/5+49/8]=4917
x[10*5*8+21*3*8+49*3*5]
= 4917*3*5*8
x[400+504+734]=4917*3*5*8
x[1639]=590040
x=590040/1639=360
x=360.
put the value of x into equation 1 and we get,
10/3x=1200,
21/5x=1512,
49/8x=2205.
we get the three numbers are 1200, 1512, and 2205.
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