Question

The sum of 3 numbers 88 the 2nd number is 5 times of one fourth of the first number and the 3rd number is 10 more than the 1st number. Find the three numbers.

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Answer 1

Step-by-step explanation:

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Answer 2

Given :-

The sum of 3 numbers 88 the 2nd number is 5 times of one-fourth of the first number and the 3rd number is 10 more than the 1st number

To Find :-

Numbers

Solution :-

Let

Numbers = x,y and z

x + y + z = 88 (1)

Now,

A/Q

Second number = 5 × 1/4 of first number

Second number = 5 × 1/4 × x

Second number = 5x/4

And,

Third numbers = 10 more than the first number

Third number = x + 10

Now,

x = x

y = 5x/4

z = x + 10

On putting these values in Eq. 1

x + 5x/4 + x + 10 = 88

4x + 5x + 4x/4 = 88 - 10

13x/4 = 78

x = 78 × 4/13

x = 6 × 4

x = 24

Since, x = 24

y = 5 × 24/4

y = 5 × 6

y = 30

z = x + 10

z = 24 + 10

z = 34

Hence,

Numbers are 24,30,34