Question

The sum of 3 numbers, A,B and C,is 2468. A is 580 and B is twice of A . The value of C is

Answer 1

Step-by-step explanation:

Let a,b,c be the three numbers

Given a+b+c = 15 _________ (1)

(a+c) - b = 5 _________ (2)

(2a + b) - c = 4 _________ (3)

a+b+c=15 _____ (1)

a-b+c= 5 ______ (2)

2a+b-c = 4 _______ (3)

(1)+(2) ⇒ a+b+c+a-b+c = 15+5

2a+2c=20 (or) a+c= 10 ________ (4)

substituting (4) in (1) ⇒ b+(a+c) = 15

⇒ b+10=15

⇒ b= 15 - 10 = 5

equation (1) + equation (3)

⇒ a+b+c+2a+b-x= 15+4

⇒ 3a+2b=19 ⇒ 3a =19-2b

⇒ 3a=19-2(5)

⇒ 3a=19-10 = 9

∴a=9/3=3

∴ a = 3 , b = 5

put a = 3, b = 5 in (1) we get

3+5+c = 15

⇒ c = 15 - 8 = 7

∴ a = 3 b = 5 c = 7.