Question

The sum of 3 numbers are 10/3 : 21/5 : 49/8 is 4917. Find the numbers....​

Answer 1

The ratio of the numbers is

10/3 : 21/5 : 49/8

Let, x be the common multiple.

Then the numbers are

10x/3, 21x/5 and 49x/8

Given that :

10x/3 + 21x/5 + 49x/8 = 4917

or, (10/3 + 21/5 + 49/8)x = 4917

or, 1639x/120 = 4917

or, 1639x = 4917×120

or, x = (4917×120)/1639

or, x = 3×120 [since 4917=3×1639]

So, x = 360

Therefore, the numbers are

1200, 1512 and 2205. ok dear follow me ✌️ samile ✌

Answer 2

Answer:

hope it helps ✌️