Question

The sum of 3 numbers in A.P. is -6, and their product is 64. Find the numbers.

Answer 1

Hey friend

Let the 3 numbers be (a-d),a, (a+d)
Sum of numbers =

... 3a=. -6
So a = -2...............*

Now product of numbers (-2-d)(-2)(-2+d)
(4-2d+2d-d^2)(-2)
(4-d^2)(-2)
=> 2d^2 -8 = 64(given)
So 2d^2 = 72
.. D^2=36
Hence D = +-6

When d=6
Numbers are= -8,-2,4.

When d=-6
Numbers are 4,-2,-8.

Hope this will help you.
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