Question

The sum of 3 numbers in an A.P is -3 and their product is 8 find their numbers (please show working)

Answer 1

Answer:

-4,-1,2or2,-1,-4

Step-by-step explanation:

now product of three numbers is given by a,a+d,a-d

∴ by given condition a+a+d+a-d=-3

∴3a=-3

∴a=-1

now product of three numbers that is by second condition

∴a(a+d)(a-d)=8

∴(a²-d²)a=8

∴a³-ad²=8

∴-1+d²=8

∴d²=8+1

∴d²=9

∴√d=√9

∴d=±3

now if

d=-3

then three numbers will be

-4,-1,-2

and if

d=3

then three numbers will be

2,-1,-4

Answer 2

Answer:

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