The sum of 3 numbers in an ap is -15 and their product is- 80
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Answer:
THIS IS HOW YOU DO IT
Step-by-step explanation:
LET THE THREE NUMBERS BE a,(a-d) and (a+d)
NOW THEIR SUM IS -15 HENCE
(a-d)+a+(a+d)=-15
3a=-15
a=-5
NOW THEIR PRODUCT IS -80.HENCE
a(a-d)(a+d)=-80
a(a^2-d^2)=-80
a^3-ad^2=-80
put value of a
(-5)^3-(-5)d^2=-80
-125+5d^2=-80
5d^2=-80+125
d^2=45/5
d^2=9
therefore d=3 or d=-3
hence numbers become
when a=-5 and d=3
numbers are -2,-5 and -8
WHEN a=-5 and d=-3
numbers are -2,-5,-8
HENCE THEY ARE SAME
THEREFORE THE NUMBERS IN AP ARE -2,-5,-8
HOPE I HELPED YOU
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