The sum of 3 numbers in an arithmetic progression is 30. The sum of their squares is 302. Find the largest among the three numbers.
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Step-by-step explanation: Let the terms of the AP be a-d, a and a+d.
Given, sum = 30
a-d + a + a+d = 30
=> 3a = 30
=> a = 10
Sum of squares = 302
(10-d) ^2 + 10^2 + (10+d) ^2 = 302
=> 300+2d^2 = 302
=> 2d^2 = 2
=> d = 1 and -1
Largest number will be a+d = 10+1 =11
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