Question

The sum of 3 numbers in AP is 30 and the product of the extreme numbers is 96.The first term of the AP is
A)12
B)8
C)20
D)66​

Answer 1

Step-by-step explanation:

hi friend ,here is ur answer

let , the three terms in an A.P is

( a-b) , a, ( a+ b)

according to the problem

the sum of three terms is 30

(a-b) +a+(a+b) = 30

3a = 30

a= 10

AND the product of extreme term is 96

then (a-b) × (a+b) = 96

that is a^2 - b^2 = 96

= (10) ^2 - b^2 = 96

= 100 - b^2 = 96

= b^2 = 100 - 96

= b^2 = 4

= b = √4

= b= 2

then, let case.1

= a, a-b,a+b

= 10, 8 ,12

then let case.2

= a+b,a,a-b

= 12,10,8

so mark me as a brain list