Question

The sum of 3 numbers is 130. The third number is 4 times the second. The first number is 10 more than the second. What are the numbers?

Answer 1

Given :

• Sum of three numbers = 130
• The third number is 4 times the second number
• Fist number is 10 more than second number

To find :

The three numbers

Let :

• First number = x
• Second number = y
• Third number = z

Solution :

According to question , sum of three numbers = 130

➝ x + y + z = 130 equation 1

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The third number is 4 times the second number

➝ z = 4y equation 2

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Fist number is 10 more than second number

➝ x = y + 10. equation 3

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Put value of x and z in equation 1

➝ ( y+10 ) + y + 4y = 130

➝ y + 10 + 5y = 130

➝ 6y = 130 - 10

➝ 6y = 120

➝ y = 120/6

➝ y = 20

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put value of y in equation 2

➝ z = 4(20)

➝ z = 80

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Put value of y in equation 3

➝ x = (20) + 10

➝ x = 30

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ANSWER :

Numbers are 30 , 20 , 80

Answer 2

Answer:

refer to the attachment

Step-by-step explanation:

hopefully it will work ☺️☺️