Question

the sum of 3 numbers is 98.if the ratio of the first to the second is 2:3 and that of the second to the third is 5:8,find the three numbers

Answer 1

LCM of 3 and 5 is 15

Ratio of first two numbers =(2*5)/(3*5)=10/15

Ratio of second to third numbers =(5*3)/(8*3) =15/24

Ratio of A:B:C is 10:15:24

Then, if there sum is 98

Now,

Let the Numbers be 10x,15x and 24x

10x+15x+24x=98

49x=98

x=98/49

x=2

Now, numbers are :-

10*2=20

15*2=30

24*2=48

Numbers are 20,30 and 48

I hope this will help you

-by ABHAY

Answer 2

Hey,sup!

As per the question,

Let the three numbers be x,y and z.

x+y+z=98.

x:y=2:3.
y:z=5:8.

Doing reverse N.

We get,
x:y:z= 10:15:24.

So x ,y and z be 10k,15k and 24k respectively.

10k+15k+24k=98.
49k=98.
k=98/49=2.

So the first number=10k=10×2=20.
Second number=15k=15×2=30.
Third number= 24k=24×2= 48.

Hope it helps.