Question

The sum of 3 numbers of an AP is 27 and product is 405. Find the numbers

Answer 1

Hello here is your answer by Sujeet yaduvanshi ☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝


Question:-The sum of 3 numbers of an AP is 27 and product is 405. Find the numbers.


Let to be required Number be (a-d),(a+d)and a

then,

Sum of Number=(a-d)+(a+d)+a=27
3a=27
a=27/3
a=9


then,

Product of the Number=(a+d)(a-d)(a)=405
a(a²-d²)=405
9(9²-d²)=405
9(81-d²)=405
729-9d²=405
-9d²=405-729
-9d²=-324
9d²=324

d²=324/9

d²=36

d=√36

d=6


then,

Hence,
a=9
d=6

The required Number be. 3,9,15


that's all

@Sujeet