Question

The sum of 3 numbers of an AP is 27 and their product is 405. Find the number​

Answer 1

Answer:

3,9,15

Step-by-step explanation:

let

three number a-d,a,a+d

sum of their AP=27

a-d+a+a+d=27

3a=27

a=27/3=9

similarly

product their number=405

(a-d)*a(a+d)=405

(9-d)*9(9+d)=405

(81-d²)=405/9

81-d²=45

-d²=45-81

-d²=-36

d=√36=6

so,

the number are

a-d=9-6=3

a=9

a+d=9+6=15

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