The sum of 3 single digit numbers is 15 less than their product . If we subtract 2 from first given number then sum of these numbers will become 7 more than their product. The product of given 3 numbers will be?
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Answer:
let the numbers be x,y, z
x+y+z=xyz-15 & (x-2)+y+z=(x-2)yz+7
by solving them we get yz=12
the y, z may be 2,6 or 3,4:
but 3, 4 are satisfying the above condition from that we get x=2;
hence the product xyz=2*3*4=24
Thanks.....
I hope it helps......
Ranveer07:
hello
Answered by
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xyz=x+y+z+15
(x-2)yz+7=x+y+z-2
yz=12
y=3
z=4
(y=2,z=6 is not possible for both the conditions)
12x=x+22
x=2
product =2×3×4 = 24
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