Question

The sum of 3 terms is 33 and there product is 1155 find the term​

Answer 1

let the numbers be a-d , a ,a+d

we know,

=>a-d+a+a-d=33

=>3a=33

=>a=11

We also know that

(a-d)(a+d)(a)=1155

a²-d²(a)=1155    ([a+b][a-b]=a²-b²)

we know the value of a i.e. 11

11²-d²(11)=1155

121-d²=1155/11

121-d²=105

-d²=105-121

-d²=-16

d²=16

d=√16

d=4

So, the numbers are

a+d=>4+11=15

a=11

a-d=>11-4=7

Therefore your answer is 7,11,15