The sum of 3 terms is 33and there product is 1155 find the term
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let the first term be a+d , second term a ,nd third term a-d
a+d+a+a-d=3
3a=33
a=11-----eq1
(a+d) (a) (a-d)=1155
(d²+a²)a=1155
substitution of value of a,
d²+1²=1155/1
d²=1155+1
d²=1156
√d²=√1156
d=34
by substituting the value of a nd d u will get the first second Nd third term
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