Question

The sum of 3 terms of a G.P is 19/10 and their product is-1 Find the terms​

Answer 1

Answer:

LET the terms be a/r, a, ar

Product =a^3 =-1

Then a=-1

Sum =a/r+a+ar=19/10

-1/r-1-r=19/10

-1/r-r=29/10

10r^2 +29r+10=0

(2r+5)(5r+2)=0

Therefore r=-2/5 or - 5/2

Hence the numbers are 5/2,-1,-2/5

or - 2/5,-1,5/2