Question

. The sum of 3 terms of an AP is -6 and their product is 64.Find the terms

Answer 1

Step-by-step explanation:

let 3 tems be:-

(a-d); a ; (a+d).

a-d+a+a+d = -6.

3a = -6.

a = -2.

(a-d)(a+d)(a) = 64

(a² - d²)(a) = 64

[(-2)² - d²](-2) = 64.

4 - d² = -32.

d² = 36.

d = 6.

Terms are ---> -8 , -2 , +4.

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